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Q: What is 1 1 1 1 1 1 1 1 1 1 1x0 1?

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2, realiza-se a multiplicação primeiro

1+1+1+1x0 1+1+1+0 1+1+1 3

1

-19x/38xy = -1x0/y = -1/y

ANY number multiplied by 0 = 0.

1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1x0=

6-1x0+2/2=7 Order of operations requires that multiplication and division be performed first. 6-(1x0)+(2/2)=7 I've added parenthesis to make the math a bit clearer. 6-(0)+(1)=7 And Voila, the answer is 7.

Order of operations has the multiplication happen first and then the addition.1+1+1+1+1+1+1x0+1=1+1+1+1+1+1+0+1=7All the addition can happen in the same step.

Multiplication and division first, addition and subtraction second. Without brackets, that equation equals 2.

1+1+1+1+1+1+1+1+1-1+1+1+1+1x0=

Anything multiplied by zero is zero - no matter how complex the sum !

7

7

b0m 1x0

7

61 x 02 = 122

14

I saw this on facebook and an astounding amount of people got it wrong, including some self proclaimed teacher (god help her students). Since you do not have the signs in I can just say this.Multiply first. If it says 2+1x0 then it is not two and one are multiplied by 0, it is just the 1, so the sum becomes 2 + 0.I.e. the answer is NOT zero-------------------------------------------------------------------------------I can not understand the above answer . The fact is that ANY number multiplied by 0 = 0.

When any number is multiplied by zero, the product is zero.

7 6 - 1 x 0 + 1 1. Multiplication first (PEMDAS), 1x0 = 0 2. Division, Addition, Subtraction.... 6-0+1= 7

Let y = 3x y' = 3(x)' y' = 3(x1)' y' = 3[1x(1-1)] y' = 3(1x0) y' = 3(1 x 1) y' = 3 In general: y = xn y' nx(n-1)

7. But, the answer can also be 4. This is an ambiguous question. If the question is interpreted in this way : 6- (1x0) + (2/2), then the answer is 1 [6-0+1 = 7]. But, if the question is interpreted as : [6-(1x0) + 2]/2 ------- when the whole term is divided by two, the answers is 2 [(6-0+2)/2 = 8/2 = 4].

Here: 9+8+7+6+4+3+2+1x0=0 and then 0+5=5

If that's 6 x 102 divided by 2, the odpowiedz is 3 x 102 If that's 6 - 1 x 0 + 2/2, the order of operations states that multiplication and division take place before addition and subtraction. 1 x 0 = 0 and 2/2 = 1 6 - 0 + 1 = 7

double the number of itself , but when it is 1 or 0 , for 1 , you get 1 , for 0 you get 0 . Meaning for example , 1 . 1x1=1 2x1=2 3x1=3 4x1=4 The 2nd example would be , 1x0=0 2x0=0 3x0=0 4x0=0